(x-5)(x^2+2x-24)=0

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Solution for (x-5)(x^2+2x-24)=0 equation: 


Simplifying
(x + -5)(x2 + 2x + -24) = 0

Reorder the terms:
(-5 + x)(x2 + 2x + -24) = 0

Reorder the terms:
(-5 + x)(-24 + 2x + x2) = 0

Multiply (-5 + x) * (-24 + 2x + x2)
(-5(-24 + 2x + x2) + x(-24 + 2x + x2)) = 0
((-24 * -5 + 2x * -5 + x2 * -5) + x(-24 + 2x + x2)) = 0
((120 + -10x + -5x2) + x(-24 + 2x + x2)) = 0
(120 + -10x + -5x2 + (-24 * x + 2x * x + x2 * x)) = 0
(120 + -10x + -5x2 + (-24x + 2x2 + x3)) = 0

Reorder the terms:
(120 + -10x + -24x + -5x2 + 2x2 + x3) = 0

Combine like terms: -10x + -24x = -34x
(120 + -34x + -5x2 + 2x2 + x3) = 0

Combine like terms: -5x2 + 2x2 = -3x2
(120 + -34x + -3x2 + x3) = 0

Solving
120 + -34x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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